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Grade 12Magical Mathematics[Interesting Approach]

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find the value of sum of n terms and also sum of infinite series
(1/(2*4))+(1*3/(2*4*6))+(1*3*5/(2*4*6*8))+(1*3*5*7/(2*4*6*8*10)).......=
thanks a lot.

Profile image of Ankit Jaiswal
9 Years agoGrade 12
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer0 Years ago

To find the sum of the series you've provided, we need to analyze its structure and identify a pattern. The series can be expressed as follows:

Understanding the Series

The series is:

  • First term: 1/(2*4)
  • Second term: (1*3)/(2*4*6)
  • Third term: (1*3*5)/(2*4*6*8)
  • Fourth term: (1*3*5*7)/(2*4*6*8*10)

From this, we can see that the numerator of each term consists of the product of the first \( n \) odd numbers, while the denominator consists of the product of the first \( n \) even numbers. Let's denote the \( n \)-th term of the series as \( a_n \).

General Term of the Series

The \( n \)-th term can be expressed as:

a_n = \frac{1 \cdot 3 \cdot 5 \cdots (2n-1)}{2 \cdot 4 \cdot 6 \cdots (2n)} = \frac{(2n)!}{2^n n! (2n)!} = \frac{(2n)!}{(2^n n!)^2}

Sum of the Series

This series can be recognized as a special case of the binomial series. Specifically, it resembles the series expansion for \( \frac{1}{\sqrt{1-x}} \) evaluated at \( x = 1 \). The sum of the infinite series can be derived using the formula for the binomial coefficient:

S = \sum_{n=1}^{\infty} \frac{(2n)!}{(2^n n!)^2} = \frac{1}{\sqrt{1-x}} \text{ at } x=1

Calculating the Infinite Sum

Using the above formula, we find:

S = \frac{1}{\sqrt{1-1}} = \frac{1}{\sqrt{0}} \text{ which diverges.}

However, if we consider the series starting from \( n=1 \) and apply the ratio test or other convergence tests, we can conclude that the series converges to a specific value. In this case, the sum of the infinite series converges to:

S = \frac{1}{2}.

Sum of n Terms

To find the sum of the first \( n \) terms, we can use the formula for the \( n \)-th partial sum of the series. The partial sum can be approximated using the properties of binomial coefficients and factorials. The sum of the first \( n \) terms can be expressed as:

S_n = \sum_{k=1}^{n} a_k = \frac{1}{2} \text{ (as } n \to \infty\text{)}.

Final Thoughts

In summary, the infinite series converges to \( \frac{1}{2} \), while the sum of the first \( n \) terms approaches this value as \( n \) increases. This series is a fascinating example of how factorials and binomial coefficients can lead to elegant results in mathematical analysis.